 | University of St. Andrews - 1903 - 762 lapas
...between the centres of two adjacent faces, and the diagonal of the cube. C. 14. Find an expression for the area of a triangle in terms of two sides and the included angle. Show that Jc2 sin B (cos B + sin B cot C) is an expression for the area of the triangle ABC. 15. How... | |
 | George Sarton - 1922 - 674 lapas
...off* — 2-ab-ag- cos bag, ab ag- sin bag = ad-bg. The first implicit statement of the formula for the area of a triangle in terms of two sides and the sine of the included angle appears to be proposition 26 : « The area of a triangle and the product... | |
 | Thomas Percy Nunn, Sir Thomas Percy Nunn - 1914 - 760 lapas
...equivalence area = £ca sin /? still remains, the second formula becomes area = \bc sin (180° - a). That is to say, we cannot express the area of a triangle...agreeing that angles between 90° and 180° shall be considered to have sines, the rule being that sin a = sin (180° - a) — or, in words, that the... | |
 | Sir Thomas Percy Nunn - 1914 - 654 lapas
...equivalence area = $ca sin /? still remains, the second formula becomes area = $bc sin (180° - a). That is to say, we cannot express the area of a triangle...agreeing that angles between 90° and 180° shall be considered to have sines, the rule being that sin a = sin (180° - a) — or, in words, that the... | |
 | Herbert Ellsworth Slaught - 1914 - 296 lapas
...S=%bc where c is the base and b the altitude. We therefore have a single formula S =1 be sin A 2 for the area of a triangle in terms of two sides and the included angle, whether the latter be acute, right, or obtuse. 41. The law of sines. Since the triangle has three angles... | |
 | Ernest Julius Wilczynski - 1914 - 296 lapas
...formula reduces to S=%bc where c is the base and b the altitude. We therefore have a single formula for the area of a triangle in terms of two sides and the included angle, whether the latter be acute, right, or obtuse. 41. The law of sines. Since the triangle has three angles... | |
 | Selig Brodetsky - 1920 - 160 lapas
...-1-5 • 1 6 C b Area a FIG. 52. metrical functions. Let us take, as an illustration, the formula for the area of a triangle in terms of two sides and the included angle. If we take the nomogram for the product of three quantities (Fig. 31) and use a instead of A, b instead... | |
 | I.M. Gelfand, Mark Saul - 2001 - 244 lapas
...acute triangle ABC, show that c = a cos B + bcosA. 8 Two remarks Remark 1: Note that these formulas express the area of a triangle in terms of two sides and an included angle. We knew from geometry that these three pieces of information determine the triangle... | |
 | University of Bombay - 1911 - 362 lapas
...Find the height of the top of the tower, given that tan 48° - 1-1106 and tan 87' « 19'0811. 4. Find the area of a triangle in terms of two sides and the included angle. Two equal fences 6-5 chains in length bound a triangle whose area is 1 acre 3 roods. I' md the length... | |
 | 220 lapas
...9. 7. 19, 18, 17. 8. 43, 27, 32. 9. 45, 27, 21. 10. 117, 210, 184. CHAPTER XVII. AREAS. 133. To find the area of a triangle in terms of two sides and the included angle. A Let ABC be the triangle, the angle В being acute, and the angle С being either acute, obtuse or... | |
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That is to say, we cannot express the area of a triangle in terms of two sides and the included angle... 
