| Madras literary society - 1837
...which AE is the other kg, and AB, is the third side, or hypothenuse. Then, as in right angle triangles, **the square of the hypothenuse is equal to the sum of the** squares of the other two sides; in the right angle triangle AEB,— BE8 -f- AE JL AB* : but as BE,... | |
| Charles Guilford Burnham - 1837 - 256 páginas
...the hypothenuse, having the other two sides given ? Base. 9 2 AC=9=81 In every right angled triangle, **the square of the hypothenuse is equal to the sum of the** squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the... | |
| Jeremiah Day - 1838
...are referred to. 94. Other relations of the sine, tangent, &c., may be derived from the proposition, **that the square of the hypothenuse is equal to the sum of the** squares of the perpendicular sides. (Euc. 47. 1.) In the right angled triangles CBG, CAD, and CHF.... | |
| Charles William Hackley - 1838 - 307 páginas
...last, and a very simple formula depending upon the well known property of the right angled triangle, **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides, a formula expressing the value of the sine of half an arc in terms... | |
| 1838
...equal, and together forming an inscribed square to the circle AB C D. Then, as in right angle triangles, **the square of the hypothenuse is equal to the sum of the** squares of the other two sides, in the right angle triangle AEB, B Е 2 +Л E 2 = AB 2 : but as BE,... | |
| Perry Fairfax Nursey - 1838
...К is the other leg, and AB, is the third side, or hypothenuse. Then, as in right angle triangles, **the square of the hypothenuse is equal to the sum of the** squares of the other two sides, in the right angle triangle AEB, В Е=+Л E-' = A ß2: but as BE,... | |
| Jeremiah Day - 1839 - 370 páginas
...Therefore R2=cos xsec. 94. Other relations of the sine, tangent, &c., may be derived from the proposition, **that the square of the hypothenuse is equal to the sum of the** squares of the perpendicular sides. (Euc. 47. 1.) In the right angled triangles CBG, CAD, and CHF,... | |
| Charles Davies - 1839 - 261 páginas
...found by either of the four last cases : or, if two of the sides are given, by means of the property **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides. Or the parts may be found by Theorem V. EXAMPLES. l. In a right-angled... | |
| Charles Davies - 1839 - 261 páginas
...found by either of the four last cases : or, if two of the sides are given, by means of the property **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides. Or the parts may be found by Theorem V. EXAMPLES. 1. In a right-angled... | |
| Nathan Daboll - 1839
...base, is yj rods 7 6SY.l9,5=*W7,5i.==5i, IT. 37J rod.. ART. 2. — In every right-angled triangle, **the square of the hypothenuse is equal to the sum of the** squares of the other two sides. 1. Hence, when the legs are given, to find the hypothenuse. RULE. Add... | |
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