these two is somewhere upon one of those straight lines, and the other upon the other line. Thus the angle which is contained by the straight lines a b, cb, is named the angle a b c, or cba; that which is contained by a b, db, is named the angle a bd, or dba; and that which is contained by d b, cb, is called the angle dbc, or cbd; but if there be only one angle at a point, it may be expressed by a letter placed at that point; as the angle at e. X. When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it. XI. An obtuse angle is that which is greater than a right angle. XII. An acute angle is that which is less than a right angle. XIII. A term or boundary is the extremity of any thing. XV. A circle is a plain figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another. XVI. And this point is called the centre of the circle. XVII. A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference. XVIII. A semicircle is the figure contained by a diameter and the part of the circumference cut off by the diameter. XIX. A segment of a circle is the figure contained by a straight line, and the circumference it cuts off. XX. Rectilineal figures, are those which are contained by straight lines. XXI. Trilateral figures, or triangles, by three straight lines. XXIII. Multilateral figures, or polygons, by more than four straight lines. XXIV. Of three-sided figures, an equilateral triangle is that which has three equal sides. XXV. An isosceles triangle is that which has only two sides equal. Isosceles. Scalene. Equilateral. XXVI. A scatene triangle is that which has three unequal sides. XXVII. A right-angled triangle is that which has a right angle. XXVIII. An obtuse-angled triangle is that which has an obtuse angle. Right-angled. Acute-angled. XXX. Of four-sided figures, a square is that which has all its sides equal, and all its angles right angles. Oblong. Square. XXXI. An oblong is that which has all its angles right anglės, but has not all its sides equal. XXXII. A rhombus is that which has all its sides equal, but its angles are not right angles. Rhombus. XXXIII. A rhomboid is that which has its opposite sides equal to one another, but all its sides are not equal, nor its angles right angles. XXXIV. All other four-sided figures besides these are called trapeziums. XXXV. Parallel straight lines are such as are in the same plane, and which, being produced ever so far both ways, do not meet. POSTULATES. I. Let it be granted that a straight line may be drawn from any one point to any other point. II. That a terminated straight line may be produced to any length in a straight line. III. And that a circle may be described from any centre, at any distance from that centre. AXIOMS. I. Things which are equal to the same thing are equal to one another. II. If equals be added to equals, the wholes are equal. III. If equals be taken from equals, the remainders are equal. IV. If equals be added to unequals, the wholes are unequal. V. If equals be taken from unequals, the remainders are unequal. VI. Things which are double of the same, are equal to one another. VII. Things which are halves of the same, are equal to one another. VIII. Magnitudes which coincide with one another, that is, which exactly fill the same space, are equal to one another. IX. The whole is greater than its part. XII. If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles, these straight lines being continually produced, shall at length meet upon that side on which are the angles which are less than two right angles. PROPOSITION I.-PROBLEM. To describe an equilateral triangle upon a given finite straight line. LET ab be the given straight line; it is required to describe an equilateral triangle upon it. From the centre a, at the distance ab, describe (3 post.) the circle bcd, and from the centre b, at the distance ba, describe the circle ace; and from the point c, in which the circles cut one another, draw ld b the straight lines (1 post.) ca, cb, to the points a, b; abc shall be an equilateral triangle. Because the point a is the centre of the circle bod, ac is equal (15 def.) to ab; and because the point b is the centre of the circle ace, bc is equal to ba: but it has been proved that ca is equal to a b; therefore ca, cb, are each of them equal to ab; but things which are equal to the same are equal to one another (1 ax.); therefore ca is equal to cb; wherefore ca, ab, bc are equal to one another; and the triangle abc is therefore equilateral, and it is described upon the given straight line a b. Which was to be done. PROPOSITION II.-PROBLEM. d с From a given point to draw a straight line equal to a given straight line. LET a be the given point, and bc the given straight line; it is required to draw from the point a a straight line equal to bc. From the point a to b draw (1 post.) the straight line ab; and upon it describe (i. 1) k the equilateral triangle d a b, and produce (2 post.) the straight lines da, db, to e and h f; from the centre b, at the distance bc, describe (3 post.) the circle cgh, and from the a centre d, at the distance d g, describe the b circle gkl. al shall be equal to bc. Because the point b is the centre of the circle cgh, b c is equal (15 def.). to bg; and because d is the centre of the circle gkl, di f is equal to dg, and da, db, parts of them, are equal; therefore the remainder al is equal to the remainder (3 ax.) bg; but it has been shewn that bc is equal to bg; wherefore al and bč are each of them equal to bg; and things that are equal to the same are equal to one another; therefore the straight line al is equal to bc. Wherefore from the given point a a straight line al has been drawn equal to the given straight line bc. Which was to be done. og B e PROPOSITION III. PROBLEM. From the greater of two given straight lines to cut off a part equal to the less .. LET ab and c be the two given straight lines, d whereof a b is the greater. It is required to cut off from a b, the greater, a part equal to C, the less. From the point a draw (i. 2) the straight line a d equal to c; and from the centre a, a b and at the distance a d, describe (3 post.) the circle def; a e shall be equal to C. Because f a is the centre of the circle d ef, a e is equal to a d; but the straight line c is likewise equal to ad; whence ae and care each of them equal to ad; therefore the straight line a e is equal (1 ax.) to c, and from a b, the greater of two straight lines, a part a e has been cut off equal to c the less. Which was to be done. PROPOSITION IV.-THEOREM. If two triangles have two sides of the one equal to two sides of the other, each to each ; and have likewise the angles contained by those sides equal to one another, they shall likewise have their bases, or third sides, equal; and the two triangles shall be equal; and their other angles shall be equal, each to each, viz. those to which the equal sides are opposite. a d LET a b c d e f be two triangles, which have the two sides a b, a c equal to the two sides de, df, each to each, viz. a b to de, and a c to df; and the angle bac equal to the angle edf, the base bc shall be equal to the base ef; and the triangle a b c to the triangle def; and the other angles to which the equal b се sides are opposite, shall be equal, each to each, viz. the angle a b c to the angle def, and the angle a cb to dfe. For, if the triangle a bc be applied to def, so that the point a may be on d, and the straight line a b upon de; the point b shall coincide with the point e, because ab is equal to de; and a b coinciding with de, a c shall coincide with d f, because the angle bac is equal to the angle edf; wherefore also the point c shall coincide with the point f, because the straight line ac is equal to df: but the point b coincides with the point e; wherefore the base b c shall coincide with the base ef, because the point b coinciding with e, and c with f, if the base b c does not coincide with the base e f, two straight lines would enclose a space, which is impossible (10 ax.). Therefore the base b c shall coincide with the base e f, and be equal to it. Wherefore the whole triangle a b c shall coincide with the whole triangle def, and be equal to it; and the other angles of the one shall coincide with the remaining angles of the other, and be equal to them, viz. the angle a b c to the angle d e f, and the angle a cb to dfe. Therefore, if two triangles have two sides of the one equal to two sides of the other, each to each, and have likewise the angles contained by those sides equal to one another, their bases shall likewise be equal, and the triangles be equal, and their other angles to which the equal sides are opposite shall be equal, each to each. Which was to be demonstrated. PROPOSITION V.-THEOREM. The angles at the base of an isosceles triangle are equal to one another; and if the equal sides be produced, the angles upon the other side of the base shall also be equal. LET a b c be an isosceles triangle, of which the side a b is equal to a C, and let the straight lines a b, ac be produced to d and e, the angle a bc shall be equal to the angle a c b, and the angle cbd to the angle bce. |